In the reaction of benzene with dichlorometha | vedclass

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Question

(A) The reaction of benzene with dichloromethane $(CH_2Cl_2)$ in the presence of anhydrous $AlCl_3$ is a Friedel-Crafts alkylation reaction.First,benz

Vedclass · Accepted Answer

Benzyl chloride $(C_6H_5CH_2Cl)$

Vedclass · Answer

(A) The reaction of benzene with dichloromethane $(CH_2Cl_2)$ in the presence of anhydrous $AlCl_3$ is a Friedel-Crafts alkylation reaction.First,benzene reacts with $CH_2Cl_2$ to form benzyl chloride $(C_6H_5CH_2Cl)$ as the intermediate product '$A$'.Then,this intermediate '$A$' (benzyl chloride) reacts with another molecule of benzene in the presence of $AlCl_3$ to form diphenylmethane as the final product.Therefore,the intermediate '$A$' is benzyl chloride.

In the reaction of benzene with dichloromethane $(CH_2Cl_2)$ in the presence of anhydrous $AlCl_3$,the intermediate product '$A$' is:

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